What is the focal length of a lens whose power is -0.5 D?
suryavanshiabhp3ok98:
P= 1/f
-0.5 =1/f
F = 1/-0.5
F = 10/-5, multiplying numerator and denominator by 10
F = -2, is the answer
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=》 p = 1/ f
=》 - 5 = 1 / f
=》 f = - 1 / 5
=》 f = - 0. 2
=》 - 5 = 1 / f
=》 f = - 1 / 5
=》 f = - 0. 2
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but why ??
Answered by
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this is the focal length.......
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