Question

what is the fomula for maximum hight​

Answer 1

Answer:

Formula: max=0.0029/T where: = wavelength where most of the light is emitted, measured in meters. T = temperature of the object, in degrees Kelvin (K)

Answer 2

Answer:

H – ½H so h = H/2

Explanation:

Let the two side angles be equal to the launch angle θ . The maximum height h reached by the projectile is equal to one-half of H, the altitude of this triangle. = H – ½H so h = H/2, which is the desired result