Question

what is the fomula for maximum hight​

Answer 1

Explanation:

Let the two side angles be equal to the launch angle θ (see Fig. 1). The maximum height h reached by the projectile is equal to one-half of H, the altitude of this triangle. = H – ½H so h = H/2, which is the desired result.

Answer 2

Answer:

Let the two side angles be equal to the launch angle θ (see Fig. 1). The maximum height h reached by the projectile is equal to one-half of H, the altitude of this triangle. = H – ½H so h = H/2, which is the desired result. mark it as branliest answer...