What is the force a
On an object with 6n and 12n
Answers
Answer:
There are two things you have to know here other than the information you gave. First of all the mass of the object. Assuming this is an earth based object on the earth's surface, its mass will be given by Newton's equation from his second law of motion as follows : m = F/g. Now let's go to the other aspect which is the direction that you are accelerating the object, against gravity, at an angle, or horizontally. If it is against gravity then it will require more force to keep it going at that acceleration as gravity will continue to oppose the vertically upward movement dynamically. Let's assume you mean a horizontal force that will produce a horizontal acceleration. So then it's easy, the mass must be multiplied by the acceleration above. That will be as follows : f = ma = (F/g)•a = (12N/9.81ms^-2)•6ms^-2 = 7.339 N. Here f is the longitudinal force you are asking for, with the assumption also that you are on a frictionless surface. So here the great Newtonian second law of motion equation was used twice to get the answer ! Kaiser T, MD.
Answer:
There are two things you have to know here other than the information you gave. First of all the mass of the object. Assuming this is an earth based object on the earth's surface, its mass will be given by Newton's equation from his second law of motion as follows: m = F/ g. Now let's go to the other aspect which is the direction that you are accelerating the object, against gravity, at an angle, or horizontally. If it is against gravity then it will require more force to keep it going at that acceleration as gravity will continue to oppose the vertically upward movement dynamically. Let's assume you mean a horizontal force that will produce a horizontal acceleration. So then it's easy, the mass must be multiplied by the acceleration above. That will be as follows: f = ma = (F/g) a = = (12N/9.81ms^-2).6ms^-2 = 7.339 N. Here f is the longitudinal force you are asking for, with the assumption also that you are on a frictionless surface. So here the great Newtonian second law of motion equation was used twice to get the answer! Kaiser T, MD.