Math, asked by dharshanganesh349, 2 days ago

What is the force acting on a body if the velocity increases from 5 m / s to 6 m / s in 2 s and if the mass of the body is 12 Kg?​

Answers

Answered by nishantgaurav9417831
3

Given:

  • intial velocity (u) = 5m/s
  • final velcoity (v) = 6m/s
  • time (t) = 2s
  • mass = 12kg

To Find:

  • Force

Solution:

To find force we have to find acceleration (a) first

So a= (v-u)/t

=> a= (6-5)/2

=> a= 1/2

And we know

Force = mass × acceleration

F = 12 × 1/2

F = 6N

Answered by Aryan0123
13

Answer:

Force acting on the body = 6 N

\\

Step-by-step explanation:

Given:

  • Initial velocity = u = 5 m/s
  • Final velocity = v = 6 m/s
  • Time = t = 2 seconds
  • Mass of the body = m = 12 kg

\\

To find:

Force acting on the body = ?

\\

Solution:

We know that:

\bf{F=ma \quad \dashrightarrow\quad Eq^{n}\: \:1}\\\\

But we are not given the acceleration of the body.

From the First Equation of Motion;

\sf{a=\dfrac{v-u}{t}\: \quad \dashrightarrow \quad Eq^{n}\:\:2}\\\\

\\

Now, put the value of a from Equation 2 in Equation 1.

\boxed{\boldsymbol{F=m\bigg(\dfrac{v-u}{t}\bigg)}}\\\\

\\

Substitute the given values in the above Equation.

\implies \: \sf{F=12 \times \bigg(\dfrac{6-5}{2}\bigg)}\\\\

\implies \sf{F=12 \times \bigg(\dfrac{1}{2}\bigg)}\\\\

\implies\: \sf{F=6N}\\\\

\therefore \: \underline{\boxed{\bf{Force \: acting =6N}}}

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