Question

What is the force acting on a body if the velocity increases from 5 m / s to 6 m / s in 2 s and if the mass of the body is 12 Kg?​

Answer 1

Given:

• intial velocity (u) = 5m/s
• final velcoity (v) = 6m/s
• time (t) = 2s
• mass = 12kg

To Find:

• Force

Solution:

To find force we have to find acceleration (a) first

So a= (v-u)/t

=> a= (6-5)/2

=> a= 1/2

And we know

Force = mass × acceleration

F = 12 × 1/2

F = 6N

Answer 2

★ Answer:

Force acting on the body = 6 N

★ Step-by-step explanation:

Given:

• Initial velocity = u = 5 m/s
• Final velocity = v = 6 m/s
• Time = t = 2 seconds
• Mass of the body = m = 12 kg

To find:

Force acting on the body = ?

Solution:

We know that:

$\bf{F=ma \quad \dashrightarrow\quad Eq^{n}\: \:1}$

But we are not given the acceleration of the body.

From the First Equation of Motion;

$\sf{a=\dfrac{v-u}{t}\: \quad \dashrightarrow \quad Eq^{n}\:\:2}$

Now, put the value of a from Equation 2 in Equation 1.

$\boxed{\boldsymbol{F=m\bigg(\dfrac{v-u}{t}\bigg)}}$

Substitute the given values in the above Equation.

$\implies \: \sf{F=12 \times \bigg(\dfrac{6-5}{2}\bigg)}$

$\implies \sf{F=12 \times \bigg(\dfrac{1}{2}\bigg)}$

$\implies\: \sf{F=6N}$

$\therefore \: \underline{\boxed{\bf{Force \: acting =6N}}}$