What is the force between charges if distance is halved
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F = (1/4πε) ( q1 * q2 ) / (r/2)^2
F = (1/4πε) ( q1 * q2 ) 4 / r^2
therefore if distance between two point charges is halfed then the force between them becomes 4 times greater......
F = (1/4πε) ( q1 * q2 ) 4 / r^2
therefore if distance between two point charges is halfed then the force between them becomes 4 times greater......
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