Question

What is the force between two charged sphere having charges 3nc and 12nc placed 4cm apart

Answer 1

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We know that,

Force between 2 charges = kq₁q₂/r²

In the given case,

q₁ = 3μC = 3×10⁻⁶ C

q₂ = 12μC = 12×10⁻⁶ C

r = 4cm = 4×10⁻² m

Hence,

F = kq₁q₂/r²

F = 9×10⁹×3×10⁻⁶×12×10⁻⁶/(4×10⁻²)²

F = 324/16 × 10⁹⁻⁶⁻⁶⁺⁴

F = 20.25×10¹³⁻¹²

F = 20.25×10

F = 202.5 N

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