Question

what is the force between two small charge sphere having charges of 2*10^-7c and 3×10^-7 C placed 30cm apart in air?​

Answer 1

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Given :- }}}}$

• Two small charge sphere are kept 30cm apart.
• The spheres have a charge of 2 × 10-⁷ C and 3 × 10-⁷ C .

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ To Find- }}}}$

• The force between the two charges.

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Solution :- }}}}$

The two charges are positive , hence they will repel each other. The magnitude of charges are , 2 × 10-⁷ C and 3 × 10 -⁷ C . So that here we can use the Columb's Law . As ,

$\sf\dashrightarrow Force =\dfrac{ k q_1 q_2 }{r^2}$

• q₁ and q₂ are the two charges .
• r is the distance of separation .
• The value of k is 9 × 10⁹ N .m² C -² .

$\sf\dashrightarrow Force = \dfrac{ 9 \times 10^9 \times 2 * 10^{-7} C \times 3*10^{-7} C }{ (30/100 m)^2} \\\\\\\sf\dashrightarrow Force = \dfrac{ 9 \times 10^{10} \times 6 \times 10^{-14}}{3 } \ N \\\\\\\sf\dashrightarrow Force = 18 \times 10^{10-14} \\\\\\\sf\dashrightarrow\underset{\blue{\sf Required \ Force }}{\underbrace{\boxed{\pink{\frak{ Force = 1.8 \times 10^{-3} \ Newton }}}}}$