Question

What is the force between two small charged spheres having charges of 2 × 10 −7 C and 3 × 10 −7 C placed 30 cm apart in air?​

Answer 1

Answer:

answer in attachment

Answer 2

Given :-

Charge on the first sphere, q₁ = 2 × 10⁻⁷ C

Charge on the second sphere, q₂ = 3 × 10⁻⁷ C

The distance between two charges = 30 cm

To Find :-

The force between the charges.

Solution :-

We know that,

• f = Force
• r = Distance

By the formula,

$\underline{\boxed{\sf Force= \dfrac{1}{4 \pi \epsilon_0} \times \dfrac{q_1q_2}{r^2} }}$

Substituting their values,

ϵ₀ = Permittivity of free space

$\sf \dfrac{1}{4 \pi \epsilon_0} =9 \times 10^9 \ Nm^2 \ C^{-2}$

$\sf Force=\dfrac{9 \times 10^9 \times 2 \times 10^{-7} \times 3 \times 10^{-7}}{(-0.3)^2}$

$\sf Force=6 \times 10^{-3}\ N$

The force between the charges will be repulsive as they have the same nature.