Question

what is the force btween two charges of 2*10-7c placed 30 cm apart in air​

Answer 1

Answer:

F = 6 x 10^-3 N

Explanation:

Repulsive force of magnitude 6 × 10 - 3 N

Charge on the first sphere, q1 = 2 × 10 - 7 C

Charge on the second sphere, q2 = 3 × 10 - 7 C

Distance between the spheres, r = 30 cm = 0.3 m

Electrostatic force between the spheres is given by the relation,

F = (q1*q2)/ 4 π ∈o r²

here, ∈0 = Permittivity of free space

1 / ( 4 π ∈o) = 9*10^9 N m² C^-2

substituting we get,

F = 6 x 10^-3 N