Question

What is the force constant of a spring which is stretched
a) 2 mm by a force of 4 N,
b) 4 cm by a mass of 200 g?

Answer 1

Answer:

Force constant of a spring in the following cases:

2 mm by a force of 4 N

4 cm by a mass of 200 g

Calculation:

We will consider that at the given extension , the spring force is equal and opposite to the applied force.

In the 1st case:

.. force = kx

=> -4 = -k(2 × 10-³)

=> 4 = k(2 × 10-³)

k 2000 Nm -1

In the 2nd case:

... force = -kx

200 x g -k(4 x 10-²)

1000

200 1000 x 10 = k(4 × 10-²)

2000 => = k(4 × 10-²)

1000

=> 2 = k(4 × 10-²)

=> k = 0.5 × 10²

=> k = 50 Nm

Hope It Helps

PLEASE MARK BRAINLIEST