What is the force experienced by a test charge of 0.20 micro C placed in a electric field of 3.2 *10^6 N/C
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F=q *E
=( .2*10^-6 )*3.2*10^6
=.64 Nc^-1
=( .2*10^-6 )*3.2*10^6
=.64 Nc^-1
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