Question

what is the force in Newton experienced by a straight current carrying conductor carrying a current of 1 ampere and length of conductor is 1 metre when it is placed parallel to a magnetic field of 2T​

Answer 1

Given:

• Current = 1 ampere
• Length of conductor = 1 metre
• Magnetic field intensity = 2 T.

To find:

• The force experienced by the wire ?

Calculation:

• The question clearly states that the current carrying wire is parallel to the magnetic field direction. This means the angle between them is 0° (zero degree).

Now, the force will be :

$\boxed{F = i \times l \times B \times \sin( \theta) }$

$\implies F = 1\times 1 \times 2 \times \sin( {0}^{ \circ} )$

$\implies F = 1\times 1 \times 2 \times 0$

$\implies F = 0 \: N$

So, the force experienced by the current carrying wire is 0 Newton.

• So, always remember that when the wire is placed parallel to the magnetic field, it will never experience any force.

Answer 2

Explanation:

Given:

Current = 1 ampere

Length of conductor = 1 metre

Magnetic field intensity = 2 T.

To find:

The force experienced by the wire ?

Calculation:

The question clearly states that the current carrying wire is parallel to the magnetic field direction. This means the angle between them is 0° (zero degree).

Now, the force will be :

\boxed{F = i \times l \times B \times \sin( \theta) }

F=i×l×B×sin(θ)

\implies F = 1\times 1 \times 2 \times \sin( {0}^{ \circ} ) ⟹F=1×1×2×sin(0

∘

)

\implies F = 1\times 1 \times 2 \times 0⟹F=1×1×2×0

\implies F = 0 \: N⟹F=0N

So, the force experienced by the current carrying wire is 0 Newton.

So, always remember that when the wire is placed parallel to the magnetic field, it will never experience any force.