Question

what is the force necessary to stretch a copper wire (Y=1.2x10^11N/m^2) of radius 1mm by 1% ?

Answer 1

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Use the formula

Y= (F/A)/(∆L/L)

Answer 2

The force necessary to stretch the wire is F = 3678 N

Explanation:

Given data:

• Young's modulus of copper wire "Y" = 1.2 x 10^11 N / m^2
• Radius of wire "r" = 1 mm
• Stretch = 1 %

Solution:

Young's modulus formula is given by:

Y = F / A x L / ∆L

F = Y A  ∆L / L

F = ( 1 / 100 ) x 1.2 x 10^11 x 3.14 x (10^-3)^2

F = 1 / 100 x 1.2 x 10^11 x 3.14 x 10^-6

F = ( 1 / 100 ) x 3.768 x 10^5

F = 0.01 x 3.678 x 10^5

F = 3.678 x 1000

F = 3678 N

Thus the force necessary to stretch the wire is F = 3678 N