What is the force of attraction between an object of mass 10kg and 5 kg, if they are separated by a distance of 2 m. 2. If the attractive force between two objects at a distance 'd' is 'F'. If the distance between them is one-forth of initial distance, what will be the new Force?
Answers
Answered by
0
Explanation:
M1=10kg;M2=5kg,d=2m
F=GM1M2/d²=6.67×10^-¹¹(5)(10)/2²
=6.67×10^-11×50/4
=8.83×10^-10
M1=M1=10 M2=M2=5 d=d/4
F¹=GM1M2/d²
=GM1M2/(d/4)²
=16Gm1m2/d²
=16×F
=16×8.83×10^-10
=141.28×10^-10
=1.4128×10^-8
Similar questions