Question

What is the force of gravitation between two point masses of 1 kg and 2 kg kept 1 m apart

Answer 1

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Force of gravitation = 13.4 × 10^-11N

${\huge{\boxed{\mathcal{\red{Explanation}}}}}$

According to universal law of gravitation: Force of gravitation between two bodies is directly proportional to product of their masses and inversely proportional to square of distance between them. This law can be represented mathematically by some keywords that is :

$f = G \frac{Mm}{ {d}^{2} }$

Keywords :

• F = force of gravitation
• G = universal gravitational constant.
• M = mass of first body
• m = mass of second body
• d = distance between bodies

Value of universal gravitation constant is :

$6.673 \times {10}^{ - 11} n {m}^{2} \div {kg}^{2}$

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Coming to question :-

In this case the keywords are :

• M = 1kg
• m = 2kg
• d = 1m

Therefore according to universal law of gravitation, Force of gravitation between these two point masses is :

$f = 6.673 \times {10}^{ - 11} \times \frac{2 \times 1}{ {1}^{2} }$

$f = 6.673 \times {10}^{ - 11} \times 2$

$f = 13.4 \times {10}^{ - 11} newton$

Therefore the force of gravitation between these two point masses is 13.4 × 10^-11N.

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BY√\______________ SCIVIBHANSHU

THANK YOU

STAY CURIOUS

Answer 2

We have,

Mass of first object = 1 kg

Mass of the second one = 2 kg

Distance between them = 1 m

Now we know,

F = GMm/d²

Taking G = 6.7 × 10^-11 Nm²/kg²,

F = (6.7 × 10^-11 Nm²/kg²)(2 kg)(1 kg) ÷ (1 m)²

⇒F = (6.7 × 10^-11)(2) N

⇒F = 13.4 × 10^-11 N {Answer}