What is the force of gravity acting on the point of 1 km released from the height of 1 metre from the surface of the earth the radius of Earth 6.4 into 10 ki power 6 mass of the earth 6 into 10 ki power 24 kg
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Answer:
Given:
Mass of earth m1 =6 × 1024 kg
Mass of the object m2 = 1 kg
Radius of the earth =6.4 × 106 m
We need to find the force of gravity acting on the object
We know the formula of the law of gravitation
– F = (G m1 m2/r2)
Also, we know the value of universal gravitational constant G = 6.67 x 10-11 Nm2kg-2
= (6.67 x 10-11 x 6 × 1024 x 1)/ (6.4 × 106)2
F = 9.8 N
Hence the force acting on an object is F = 9.8 N
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Answer:
sorry dont know
Explanation:
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