Question

what is the force of repulsion between two argon nuclei when separated by 1nm (10^-9).The charge of an argon nucleus is +18e​

Answer 1

Answer:

The charge of each argon nuclei is 2.88e-18 C. Thus, the force between two argon nuclei 1nm apart is 7.475e-8 Newtons.

Thanks

Answer 2

Charge on an argon nuclei is, q = +18e = 18 × 1.6 × 10-19 C

Distance between the two argon nuclei, r = 10-9 m

So, force of repulsion is, F = kq2/r2

=> F = (9 × 109)(18 × 1.6 × 10-19)2/(10-9)2

=> F = 2.592 × 10-9 N

1.9