Question

What is the force on a 1,000kg elevator that is falling freely under the acceleration of gravity?

Answer 1

The only force on it is its weight, #w = 9800 N#.

Explanation:

Since it is falling freely, the only force on it is its weight, w.

#w = m*g = 1000 kg*9.8 m/s^2 = 9800 N

#To draw a Free Body Diagram, draw an elevator cage (I am sure you would get lots of points for drawing it with intricate detail) with a downward force of 9800 N.

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Answer 2

The force on a 1,000kg elevator that is falling freely under the acceleration of gravity is 9800N.

Given,

Mass of the elevator=1000kg.

To find,

force experienced by the elevator.

Solution:

F=W=mxg

m-mass of the body

g-acceleration due to gravity

g=9.8m/s^2

F=1000x9.8

F=9800N.

The force experience by the freely falling elevator is 9800N.

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