Question

What is the force required to move a body of mass 1000 kg if the co-efficient of friction is 0.4 (assume 1kg = 10 N)?

Answer 1

Answer:

ANSWER

The maximum static friction, f

s,max

=μ

s

N=0.5×2kg×10ms

−2

or, f

s,max

=10N>2.5N, which is greater than the applied horizontal force.

Hence, friction can impede the motion and the necessary required frictional force to balance the horizontal applied force will be equal.

Therefore, f=2.5N.

Answer 2

Answer:

The force required to move a body of mass 1000 kg if the co-efficient of friction is 0.4 is $4000N$

Explanation:

• We have an expression for the weight (w) as,

        $w = mg$   ....(1)

        Where m - mass of the body and

                     g - the acceleration due to gravity.

• The force can be obtained by the expression,

        $F =\mu w$     ...(2)

        Where $\mu$is the coefficient of friction

• From the question,

        Coefficient of friction ($\mu$)=$0.4$

        Mass of the body (m)  =$1000kg$

        We know,

        $g = 10m/s^2$

        After substitution, equation(1) becomes,

        $w = 1000\times 10 = 10,000N$

        Substitutes above values into equation(2)

        $F =0.4\times 10000 = 4000N$