what is the force required to stretch a steel wore
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Answer: here you are
Explanation:Young’s modulus (Y) can be written as
Y = FL / (Ae)
Rearrange the above equation
F = YAe / L
= YAL / L ………[∵ Elongation (e) = L]
= YA
= 2 × 10^11 N / m² × [1 cm² × 10^-4 m²/cm²]
= 2 × 10^7 N
The Force required is 2 × 10^7 N
[Note: I converted Area in cm² to m²]
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