what is the force required to switch a steam wire to double its length when the area is 1 sq cm and young modulus 20*10power10
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stress = strain × youngs modulus
force = strain × Y × A
strain = change in length / original length
here wire stretch to its double length so final length becomes 3l
= (3l-l)/l = 2
F = 1 ×Y ×A = 20×10^10 × 2 × 10^-4 = 40000 kN
force = strain × Y × A
strain = change in length / original length
here wire stretch to its double length so final length becomes 3l
= (3l-l)/l = 2
F = 1 ×Y ×A = 20×10^10 × 2 × 10^-4 = 40000 kN
user8898:
but the answers was 4*10^7 N
this will help you
tnk u so mch
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