what is the formula for a^3+b^3+c^3
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3+b3+c3=(a+b+c)3−[3a2(b+c)+3b2(c+a)+3c2(a+b)+6abc]a3+b3+c3=(a+b+c)3−[3a2(b+c)+3b2(c+a)+3c2(a+b)+6abc]⟹a3+b3+c3=(a+b+c)3–3[a2(b+c)+b2(c+a)+c2(a+b)+2abc]⟹a3+b3+c3=(a+b+c)3–3[a2(b+c)+b2(c+a)+c2(a+b)+2abc]
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a3+b3+c3=(a+b+c)3−[3a2(b+c)+3b2(c+a)+3c2(a+b)+6abc]a3+b3+c3=(a+b+c)3−[3a2(b+c)+3b2(c+a)+3c2(a+b)+6abc]
⟹a3+b3+c3=(a+b+c)3–3[a2(b+c)+b2(c+a)+c2(a+b)+2abc]
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