What is the formula for a-b+c whole cube?
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Hi..mate...
(a+b+c)3=(a3+3a2b+3ab2+b3)+3(a2+2ab+b2)c+3(a+b)c2+c3. (a+b+c)3=a3+b3+c3+3a2b+3a2c+3ab2+3b2c+3ac2+3bc2+6abc. (a+b+c)3=(a3+b3+c3)+(3a2b+3a2c+3abc)+(3ab2+3b2c+3abc)+(3ac2+3bc2+3abc)−3abc. (a+b+c)3=(a3+b3+c3)+3a(ab+ac+bc)+3b(ab+bc+ac)+3c(ac+bc+ab)−3abc. (a+b+c)3=(a3+b3+c3)+3(a+b+c)(ab+ac+bc)−3abc.
hope it will help u
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