What is the formula for area of triangle when given three coordinates?
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Let the given coordinates be A(x₁, y₁), B(x₂, y₂) and C(x₃, y₃).
It is simpler to do calculations and to remember the formula, if we translate the origin to vertex A.
So new coordinates will be as: (with A as the origin)
A' = (0, 0), B' = (X₂, Y₂) , C' = (X₃, Y₃)
where X₂ = x₂ - x₁ , Y₂ = y₂ - y₁
X₃ = x₃ - x₁, Y₃ = y₃ - y₁
The formula for ar(ΔABC) = 1/2 * | X₃ Y₂ - X₂ Y₃ |
This is an extremely simple formula and easy to calculate too.
It is simpler to do calculations and to remember the formula, if we translate the origin to vertex A.
So new coordinates will be as: (with A as the origin)
A' = (0, 0), B' = (X₂, Y₂) , C' = (X₃, Y₃)
where X₂ = x₂ - x₁ , Y₂ = y₂ - y₁
X₃ = x₃ - x₁, Y₃ = y₃ - y₁
The formula for ar(ΔABC) = 1/2 * | X₃ Y₂ - X₂ Y₃ |
This is an extremely simple formula and easy to calculate too.
kvnmurty:
:-)
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