What is the formula for calculating specific charge (e/m ratio)? Also please ans this question : A negative meson is 204 times heavier than an electron and a proton is 1836 times heavier than an electron. What is the ratio of specific charges of negative meson and proton? [Ans: 9:1]
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Explanation:
As given that proton has specific charge to be 9.6×107C kg−1.
Now as alpha particle is the Helium nucleus, so it must have +2 unit charge.
Specific charge of proton =mass of proton in particlespecific charge of proton
Alpha particle is doubly ionised He atom. It carries +2e charge (Twice the charge of proton and mass of alpha particle is (2 Neutrons + 2 Protons) is almost 4 times the mass of proton.
So, if Specific charge of Proton = mp+e
Then, Specific charge of Alpha particle = 4mp+2e= specific charge of proton × 1/2
So, Specific charge of alpha particle =29.6×107=4.8×107Ckg−1.
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Answer:
The balance of forces FLorentz=FZentripetal F Lorentz = F Zentripetal can be determined asem=v0r⋅B e m = v 0 r ⋅ B Substitute v0 by the here calculated termv0=√2⋅em⋅Va v 0 = 2 ⋅ e m ⋅ V a square and solve for em em=2⋅Var2⋅B2 e m = 2 ⋅ V a r 2 ⋅ B 2 Acceleration voltage Va can be modified in the experiment, the magnetic.
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