Question

What is the formula for finding out the

1.Area of the rectangle and Square.

2.Perimeter of the rectangle and square.​

Answer 1

Answer:

hᎪᎽ mᎪᏆᎬ

Ꭵ hᎾᏢᎬ ᎽᎾu ᎪᏒᎬ fᎥᏁᎬ!

Step-by-step explanation:

AREA OF RECTANGLE= LENGTH × BREADTH

AREA OF SQUARE = SIDE × SIDE OR SIDE square

PERIMETER OF RECTANGLE= 2(LENGTH+ BREADTH)

PERIMETER OF SQUARE= 4× SIDE

Answer 2

Correct Question-:

What is the formula for finding out the -:

• 1. Area of the rectangle and Square.
• 2. Perimeter of the rectangle and square.

AnswEr-:

Formula to find Perimeter of Rectangle -:

• $\underline{\boxed{\star{\sf{\blue{  Perimeter \:of\:Rectangle\: = 2( Length + Breadth) .}}}}}$

Formula to find Perimeter of Square -:

• $\underline{\boxed{\star{\sf{\blue{  Perimeter \:of\:Square \: = 4 × Side .}}}}}$

Formula to find Area of Rectangle:

• $\underline{\boxed{\star{\sf{\blue{  Area \:of\:Rectangle \: =  Length × Breadth .}}}}}$

Formula to find Area of Square:

• $\underline{\boxed{\star{\sf{\blue{  Area \:of\:Square \: = Side × Side .}}}}}$

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♤ More to Know ♤

• Rectangle-: A Rectangle is a type of quadrilateral whose two parallel sides are equal to each other and all angles of Rectangle are 90⁰ .
• ☆ Figure of Rectangle-:
• $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large Length}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large Breadth}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$
• Square-: A square is a type of quadrilateral whose all sides are equal to each other and all angles of square are 90⁰ .
• ☆ Figure of Square-:
• $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large Side\ }\put(4.4,2){\bf\large Side\ }\end{picture}$

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