what is the formula for the product of first n odd natural numbers
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Step-by-step explanation:
The idea is to "complete the factorials":
1⋅3⋅5⋯(2n−1)=1⋅2⋅3⋅4⋯(2n−1)⋅(2n)2⋅4⋅6⋯(2n)
Now take out the factor of 2 from each term in the denominator:
=(2n)!2n(1⋅2⋅3⋯n)=(2n)!2nn!
A mathematician may object that there is a small gray area about what exactly happens between those ellipses, so for a completely rigorous proof one would take my post and incorporate it into a proof by induction.
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Answered by
1
Answer:
n square is the correct answer
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