Question

what is the formula of 2sinAcosB

Answer 1

the formula for 2sinAcosB is sin(A+B)+sin(A-B)

Answer 2

Since,we know that
If A and B are any two angles then

i) Sin( A + B ) = sinA cosB +CosAsinB

ii ) sin(A- B ) = sinAcosB - CosAsinB
Implies that :-

Sin(A +B ) + sin(A - B )

= SinAcosB+cosAsinB + sinAcosB - cosAsinB

= 2sinAcosB

Therefore ,

2sinAcosB = sin( A+B ) + sin( A- B ).


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