Question

what is the formula of 3x​

Answer 1

Step-by-step explanation:

sin 3x =4\sin x\sin(60^{\circ}-x)\sin(60^{\circ}+x). We first remind of another useful trigonometric identity: \displaystyle\sin\alpha + \sin\beta +\sin\gamma -\sin(\alpha +\beta +\gamma)=4\sin\frac{\alpha +\beta}{2}\sin\frac{\beta +\gamma}{2}\sin\frac{\gamma +\alpha}{2}.