Question

What is The formula of a compound in which atoms of A form hcp lattice and atoms of B occupy 1/3 rd of the tetrahedral void

Answer 1

Answer:

CHEMISTRY

Atoms of element B from HCP lattice and those of the element A occupy 2/3 rd of tetrahedral voids. What is the formula of the compound formed by the elements A and B?

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ANSWER

Given that, atoms of B forms hcp lattice. So, the atoms at corners are shared by 6 unit cells. So, its contribution is

6

1

; Face centered atoms contribute

2

1

and middle layer atoms contribute 1 each.

So, effective number of atoms in unit cell =

6

1

×12+

2

1

×2+1×3

=2+1+3=6

Number of tetrahedral voids =2× Number of atoms forming the lattice.

=2×6=12

So, number of atoms of A=

3

2

×12=8

Number of atoms of B=6

So, A:B⇒A:B

8:6 4:3

So, formula is A

4

B

3

How satisfied are you with the answer?

Answer 2

Answer:

CHEMISTRY

Atoms of element B from HCP lattice and those of the element A occupy 2/3 rd of tetrahedral voids. What is the formula of the compound formed by the elements A and B?

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Study later

ANSWER

Given that, atoms of B forms hcp lattice. So, the atoms at corners are shared by 6 unit cells. So, its contribution is

6

1

; Face centered atoms contribute

2

1

and middle layer atoms contribute 1 each.

So, effective number of atoms in unit cell =

6

1

×12+

2

1

×2+1×3

=2+1+3=6

Number of tetrahedral voids =2× Number of atoms forming the lattice.

=2×6=12

So, number of atoms of A=

3

2

×12=8

Number of atoms of B=6

So, A:B⇒A:B

8:6 4:3

So, formula is A

4

B

3

Explanation: