Question

What is the formula of a compound in which the element Y forms ccp lattice and atoms of X occupy 1/3 of octahedral voids??

Answer 1

No of tetrahedral voids in a ccp lattice Y is "twice" as that of the no of atoms of Y.
according to the question: atoms X fills 1/3 of the voids present in Y
and number of Voids present in Y =2Y

since X fills 1/3 of voids the equation can be made as
X=(1/3)×2Y
X=(2/3) Y

Hence the formula of the compound becomes:
X₃Y₂

NOTE: 
→For Tetrahedral compounds the number void will be Twice as that of number of atoms in Y

→For Octahedral compounds the number void will be same as that of number of atoms in Y

Answer 2

Answer:

XY3

Explanation:

For N number of atoms,

There are N octahedral voids and 2N tetrahedral voids(But our question doesnt ask about tetrahedral so we wont need it).

Suppose there are n number of Y atoms

and X occupies 1/3rd of the octahedral voids = $\frac{1}{3}$ x n

So,

X:Y = $\frac{n}{3} : n$ = $\frac{1}{3} : 1$ = $1:3$

Therefore,

XY3 is the correct answer.

Hope it helps!!!

Please Mark Brainliest!!!!!!!!!