Question

What is the formula of a compound in which the element y forms ccp lattice and atoms of x occupy 2/3rd of octahedral voids ?

Answer 1

In ccp lattice,

8×1/8 + 6×1/2 = 1+3=4

In octahedral voids,

4×2/3= 8/3

Hence,

X:Y=8/3:4 = 8:12

therefore the formula is,

X8Y12 = X2Y3

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Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

• ❤.. The number of octahedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(2/3):1 or 4:3}$ and the formula of the compound is ${A4B3}$.