what is the formula of Gay-Lussac?
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Gay-Lussac's law formula
p₁ / T₁ = p₂ / T₂ , where p₁ and T₁ are initial pressure and temperature, respectively. Similarly, p₂ and T₂ are the final values of these gas parameters
Answered by
1
Gay-Lussac's law formula
p₁ / T₁ = p₂ / T₂ , where p₁ and T₁ are initial pressure and temperature, respectively. Similarly, p₂ and T₂ are the final values of these gas parameters
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