What is the formula of number of divisors ?
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We begin by writing the number as a product of prime factors: n = p a q b r c ... then the number of divisors, d( n ) = ( a +1)( b +1)( c +1)... To prove this, we first consider numbers of the form, n = p a . The divisors are 1, p , p 2, ..., p a ; that is, d( p a )= a +1
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