what is the formula of number of possible line segments from n non-collinear points
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If three points are given then the number of lines will be (3 -1) + (2 -1) = 3. Number of lines=n(n−1)2 N u m b e r o f l i n e s = n ( n − 1 ) 2 where n represents the number of non - collinear points.
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