Question

what is the formula of sin³x​

Answer 1

Step-by-step explanation:

sin(3x) = 3 sinx−4 sin³x

Answer 2

The formula of $\sin^{3} x$ is $\dfrac{1}{4} (3\sin x-\sin 3x)$.

Step-by-step explanation:

We have,

$\sin ^{3} x$

To find, the formula of $\sin ^{3} x=?$

We know that,

$\sin 3x=3\sin x-4\sin^{3} x$

⇒$4\sin^{3} x=3\sin x-\sin 3x$

⇒$\sin^{3} x=\dfrac{1}{4} (3\sin x-\sin 3x)$

∴ The formula of $\sin^{3} x=\dfrac{1}{4} (3\sin x-\sin 3x)$

Hence, the formula of $\sin^{3} x$ is $\dfrac{1}{4} (3\sin x-\sin 3x)$.