Question

what is the formula of tan(a+2b)​

Answer 1

Answer:

tan(B/2) = √sin² B / (1+cos B) = sin B / (1+cos B) If you multiply top and bottom by √1−cos B instead of √1+cos B, you get another form of the half-angle tangent formula: tan(B/2) = sin(B/2)/cos(B/2) = ± √(1−cos B) / (1+cos B )

Answer 2

Answer:

Tana-Tana×Tan^2 b +2Tanb/ 1- Tan^2 b - 2tana × tanb

Step-by-step explanation:

tan(a+2b)= tana +tan 2b /1- tana tan2b