Question

What is the formula of (x-a)(x-b)=?

Answer 1

(x-p)(x-q)+c=0 gives (x-5)(x+1)+9=0 =>x^2-4x-5+9=0 =>x^2-4x+4=0 =>(x-2)^2=0 =>x=2 or x=-2 The roots of the given equation are 2 and -2 The roots contradict with all given options in terms of a, b, or c

Answer 2

Answer:

The formula of the given terms (x-a) and (x-b) is given by

$(x-a)(x-b)= x^2- x(a+b)+ ab$

Solution:

The formula of (x-a)(x-b) can be given by expanding the formula, i.e. by multiplying both the terms within parenthesis:

Here a and b are different integers, hence

$(x-a)(x-b) = x^2- ax-bx+ ab\\\\ = x^2-(a+ b)x+ab$

Thus the formula obtained by expanding the terms (x-a) and (x-b) is given by

$(x-a)(x-b)= x^2- x(a+b)+ ab$