Question

What is the formula to find alpha minus beta whole squared

Answer 1

The formula for $\bold{(\alpha-\beta)^{2}=\alpha^{2}+\beta^{2}-2 \times \alpha \times \beta}$

To find:

The formula for $(\alpha-\beta)^{2}$

Solution:  

We know that according to algebraic expression,$(a+b)^{2}=a^{2}+b^{2}+2 \times a \times b \rightarrow(2)$

Similarly,$(a-b)^{2}=a^{2}+b^{2}-2 \times a \times b \rightarrow(2)$

Here $a=\alpha, b=\beta$

substitute the values for a and b in the above equation (2) ,  

Hence,$(\alpha-\beta)^{2}=\alpha^{2}+\beta^{2}-2 \times \alpha \times \beta \rightarrow(3)$

The above equation represents the formula for subtracting any two terms when they are squared,

Therefore, the value of $(\alpha-\beta)^{2}=\alpha^{2}+\beta^{2}-2 \times \alpha \times \beta$

Answer 2

Answer:

$(\alpha-\beta)^{2}=\alpha^{2}+\beta^{2}-2\alpha\beta$

Step-by-step explanation:

/* We know the algebraic identity:

$\boxed {(a-b)^{2}=a^{2}+b^{2}-2ab}$

Here,

$(\alpha-\beta)^{2}=\alpha^{2}+\beta^{2}-2\alpha\beta$

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