What is the formula to solve probability of a month of january having 5 sundays
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If the month is start with friday, saturday and sunday then only 5 sundays are possible
so, probability = 3/7
so, probability = 3/7
qais:
mark as the best plz
thank you for your explanation
Answered by
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No.of JANUARY month in a year = 1
n(S) = 1
No.of JANUARY with 5 sundays in a year = 1
n(E) = 1
P(E) = n(E)/n(S)
= 1/1 = 1
Therefore probability of January having 5 sundays = 1
n(S) = 1
No.of JANUARY with 5 sundays in a year = 1
n(E) = 1
P(E) = n(E)/n(S)
= 1/1 = 1
Therefore probability of January having 5 sundays = 1
wrong
certainly there is a probabilty of jan having 5 sundays then full probability i,e. 1
answer is 3/7
yes
see my explanation
ok
qais thanks for explaing me
good explanion
my pleasure :)
you report my ans so that it will be deleted
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