what is the fraction of mass of water due to neutrons ?
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Answered by
329
Water(H2O) =total mass = 1+1+16 =18g/mol
no. of neutrons in H= 0 ( in protium)
no. of neutrons in O= 8 i.e 8 g/mol
Total neutrons in water(H2O) = (2x0)+(1x8) = 8 g/mol
% mass neutrons in water= (8/18)= 0.044= 44.44%
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no. of neutrons in H= 0 ( in protium)
no. of neutrons in O= 8 i.e 8 g/mol
Total neutrons in water(H2O) = (2x0)+(1x8) = 8 g/mol
% mass neutrons in water= (8/18)= 0.044= 44.44%
Mark as best plzz....
SwOrn:
thnx for the answer ^_^
huh??
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marked!
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Answered by
45
Water(H2O) =total mass = 1+1+16 =18g/mol
no. of neutrons in H= 0 ( in protium)
no. of neutrons in O= 8 i.e 8 g/mol
Total neutrons in water(H2O) = (2x0)+(1x8) = 8 g/mol
% mass neutrons in water= (8/18)= 0.044= 44.44%
Thats it.
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