what is the fraction of the mass of water due to nuetrons
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water = h2o
no. of neutrons in H =0 (in Protium)
no. of neutron in o =8
Total neutron in water = 2*0+1*8=8
mass of 8 neutrons =8
mass of water = 18 units
% mass of neutron in water = (8/18) * 100 = 44.44
no. of neutrons in H =0 (in Protium)
no. of neutron in o =8
Total neutron in water = 2*0+1*8=8
mass of 8 neutrons =8
mass of water = 18 units
% mass of neutron in water = (8/18) * 100 = 44.44
hemant4:
thank u so much
ur wlcm
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