Question

What is the free energy change when 1 mole of water at 100?

Answer 1

Answer:

◆ Answer-

∆G = 2149 J

◆ Explanation-

# Given-

n = 1 mol

R = 8.314 J/molK

T = 100 °C = 373 K

P1 = 1 atm

P2 = 2 atm

# Solution-

Gibbs free energy change is given by formula-

∆G = nRT ln(P2/P1)

∆G = 1 × 8.314 × 373 × ln(2/1)

∆G = 8.314 × 373 × 0.693

∆G = 2149 J

Free energy change for process is 2149 J.