Question

What is the freezing point of 0.1 m glucose solution in water? For water Kf is 1.86 K kg/mol

Answer 1

Answer:

∆Tf=Kf m

= 1.86 *0.1=0.186

∆Tf=0.186

∆Tf=to of solution -tf of pure solvent

tf of solution=∆Tf+tf of solvent=0.186+273k(water f.p=0 Celsius=273k)

=273.186k

here tf of solution means the f.p of glucose in water.

hope so helpful