Chemistry, asked by mayamurakami3, 23 days ago

What is the frequency of a photon with a wavelength of 781 nm. Report your answers to three significant digits.

The frequency is = _________ s-1

Answers

Answered by samiyafathima
0

Explanation:

x² + 7x + 10 is the required polynomial.

Explanation :

According to the Question

It is given that α and β are the zeroes of a polynomial .

Sum of zeros (α+β) = -7

Product of Zeros (αβ) = 10

we need to calculate the polynomial.

As we know that if the sum of zeros and product of zeros are given we can easily calculate the polynomial .

Let the Polynomial be P(x)

• P(x) = x²-(sum of zeros)x + (product of zeros)

Substitute the value we get

➻ P(x) = x²-(-7)x + (10)

➻ P(x) = x²+7x+10

So, the required polynomial is x² + 7x + 10.

Answered by prajithnagasai
0

Answer:

v = 3.8×10¹⁴s^(-1)

Explanation:

v =  \frac{c}{wavelength}

v = frequency

c = speed of light = 3×10⁸ m/s

So, v =  \frac{3  \times  {10}^{8} m {s}^{ - 1} }{7.81 \times  {10}^{ - 7}m }  = 3.8 \times  {10}^{14}  {s}^{ - 1}

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