Physics, asked by bhumimahto1, 11 months ago

What is the frequency of a vibrating body whose time period is 2 seconds

Answers

Answered by laraibmukhtar55
73

We can calculate the frequency of a vibrating body who time period is given, by the following formula:

Formula:  frequency = f = 1/T    , where T is the time period.

putting in the values from the given data, we get:

f = 1/2

or,

frequency = f = 0.5 Hz

Hope this helped...

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Answered by ChitranjanMahajan
6

The frequency of a body with a period of 2 sec will be 0.5 Hz

  • We know that frequency is the amount or rate of occurrence of a particular movement in a given period.
  • The mathematical representation of frequency is given as follows:                                

                                         F =  \frac{1}{T} Hz

Where,

F = frequence

T = time period

  • The given time period to us is of 2 sec, putting this value in the formula we will obtain the frequency as follows:
  • F = \frac{1}{2} = 0.5 Hz

Thus, the frequency of a vibrating body with a time period of 2 sec will be 0.5 Hz.

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