what is the frequency wavelength of a photon emitted during a transition from n=5 state to the n=2 state in the hydrogen atom
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The general formula for energy of a photon at a certain energy level is
En=-13.6/n^2
E5=-13.6/25
E2=-13.6/4
∆E=-13.6/25-(-13.6/4)
=4.57*10^-19 J (note the change in unit)
E=hv
4.57*10^-19=6.63*10^-34*v
v=6.892*10^14
note that v here is frequency
now
c=v*lambda
lambda=3*10^8/6.892*10^14
=435 nm
HOPE it helps
En=-13.6/n^2
E5=-13.6/25
E2=-13.6/4
∆E=-13.6/25-(-13.6/4)
=4.57*10^-19 J (note the change in unit)
E=hv
4.57*10^-19=6.63*10^-34*v
v=6.892*10^14
note that v here is frequency
now
c=v*lambda
lambda=3*10^8/6.892*10^14
=435 nm
HOPE it helps
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