what is the full explanation of this question ??
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third one is a right answer. 300%
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P=I2R
the current was increased by 100percent
=I+100I/100=2I
p1=(2I) 2
=4I2R
percent of current in power of dissipitation
=p1-p/p.100percent
=4I2R-I2R/I2R.100percent
=3I2R/I2R.100percent
=3.100percent
=300percent
Hence:option(c)is correct
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hence :option(c)is correct!!! ❤
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