What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?
Answers
Answered by
1
Answer:
( x + 2 )² + ( y - 1 )² = r²
( - 4 + 2 )² + ( 1 - 1 )² = r²
4 = r², than we will plug in to a formula:
( x + 2 )² + ( y - 1 )² = 4
x² + 4 x + 4 + y² - 2 y +1 = 4
x² + y² + 4 x - 2 y + 1 = 0
Answer: B )
Similar questions